MODULE 7 PIPING EQUIPMENT AND SYSTEMS

The calculation examples are shown in an accordion-style display. Some questions are accompanied by equations and/or tables for quick reference. Solve the problem on your own and then click on the question to view the solution. This will help you make sense of the work as you read through the problem-solving process.

1.

For a given water piping system, a pressure of 50 ft. of head is required to produce 30 gpm water flow. How much pressure will be required to flow 60 gpm?

Equation 7.4

P2 = P1 ×(Q2Q1)2 =50×(6030)2=200 ft.

2.

Calculate the WHP of a water piping system with flow rate of 100 gpm and 30 feet head.

Equation 7.5

WHP=Q×h×SG3960=100×30×1.03960=0.76 horsepower

3.

What BHP shall be required if the pump selected has an efficiency of 75% operating at this condition?

Equation 7.6

BHP=WHPEp=0.760.75=1.0 horsepower

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